Whats's wrong with my coding?

#include%26lt;stdio.h%26gt;


int PrintToZero(int *num)


{


int val = *num;


for(val %26gt;= 0; val--)


printf(';\t%d';,val);


}


main()


{


int *n;


printf(';enter num: ';);


scanf(';%d';,%26amp;n);


PrintToZero(int *n);


getch();








}





it doesn't work.








if a enter no 10





it will show: 10 9 8 7 6 5 4 3 2 1 0





but i cant do it. pls help me.....Whats's wrong with my coding?
Your for loop looks suspect:





for ( int val = *num; val %26gt;= 0; val-- )Whats's wrong with my coding?
use for loop as :


for(;val%26gt;=0;val--)
I'm not too good at C, but it looks like you should be declaring





int n;





and not





int *n;





but otherwise it looks good to me.





One more more error; your for loop should be


for(;val%26gt;=0;val--)





(Notice the ; at the start)
I don't see why you are using pointers, while you can easily programm it without it; I'll sum some faults you've made ;-)





* your for-loop should have 3 parameters, when you leef the first one blank, you should set a ';'





*In the main-function, you shouldn't declare n as a pointer to int. just declare it as a int





*when you call for the function PrintToZero, you should give 'n' as parameter, not int *n, because its allready declared ;-)





I'll show you the code now, without pointers.; If you need more help, mail me





#include%26lt;stdio.h%26gt;





int PrintToZero(int val)


{


for(;val%26gt;=0;val--)


{


printf(';\t%d';,val);


}


}





int main(void)


{


int n;


printf(';Enter Number :';);


scanf(';%d';,%26amp;n);


PrintToZero(n);





return 0;


}